Keegan Bradley, left, and teammate Brendan Steele celebrate after getting a birdie on the 9th hole during the second round of the Franklin Templeton Shootout golf tournament, Saturday, Dec. 10, 2011, at the Tiburon Golf Club's Gold Course in Naples, Fla. Bradley and Steele ended the day with a one-stroke lead at 19-under-par.
NAPLES, Fla. (AP)—PGA Champion Keegan Bradley and Brendan Steele shot a 13-under 59 in scramble play Sunday to become the first PGA Tour rookies to win the Franklin Templeton Shootout.
Bradley and Steele took control with an eagle by Steele on No. 14 and a birdie on No. 15, finishing at 32-under 184 for a three-stroke victory over two teams.
“We played well,” Bradley said. “We got off to a slow start, kind of like we did all three days, but we played this last stretch of holes really well.”
Steele added: “We had so much fun that it made it a lot easier for us.”
Bradley and Steele had been talking about playing in Greg Norman’s event since the spring, and said they weren’t at the three-format event to “goof off.”
After sharing the lead with Champions Tour golfers Mark Calcavecchia and Nick Price following the first round of modified alternate shot, they were one ahead of them after Saturday’s better-ball.